 # How to calculate the need for cement and sand for construction

How to calculate the need for cement and sand for construction

3 minute

Know how to calculate the need for cement and sand for wall masonry to build solid house walls.

Building a house must pay attention to many aspects, one of which is to calculate the right composition of building materials.

For the construction of house walls, two important things you need to know about the comparison are cement and sand.

These two materials play an important role in determining the strength of the house’s walls.

In order not to miscalculate, here is how to calculate the need for cement and sand that you can learn.

## How to calculate the need for cement and sand for masonry source: homestratosphere.com

### 1. Pair of ½ Brick with Mix 1 PC: 3 PP

According to SNI 2008, bricks measuring 5 x 11 x 22 with a wall surface of 1 m2, the required cement material (PC) is about 14.37 kg and sand (PP) 0.04 m3.

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If the length and height of the wall to be built is 11 mx 4 m, then the following formula can be used:

• Wall surface: 11 × 4 = 44 m2
• PC volume: 14.37 x 44 = 632.28 kg then 632.28 divided by 40 (1 bag of cement 40 kg) = 15.8 bags of cement
• PP volume: 0.04 x 44 = 1.76 m3 sand

### 2. Pairs of ½ Brick with Mix 1 PC: 4 PP

The required ratio for ½ brick masonry with a mixture of 1 PC: 4 PP is 9.68 kg PC and 0.043 m3 PP.

With a constructed wall size of 11 mx 4 m, here is how to calculate the requirements for concrete and sand masonry:

• Wall surface: 11 × 4 = 44 m2
• Volume of PC: 11.5 x 44 = 506 kg then 506 divided by 40 = 12.65 bags of cement
• PP volume: 0.043 x 44 = 1.89 m3 sand

### 3. Pairs of ½ Brick with Mix 1 PC: 5 PP

For masonry ½ brick with a mixture of 1 PC 4 PP, it takes 9.68 kg PC and 0.045 m3 PP.

With a constructed wall size of 11 mx 4 m, here is the calculation:

• Wall surface: 11 × 4 = 44 m2
• PC volume: 9.68 x 44 = 425.92 kg then 425.92 divided by 40 = 10.64 bags of cement
• PP volume: 0.045 x 44 = 1.98 m3 sand

### 4. Pairs of ½ Brick with Mix 1 PC: 6 PP

While for ½ brick with a mixture of 1 PC: 6 PP, 8.32 kg PC and 0.049 m3 PP are needed.

With the size of the wall being built 11 mx 4 m, the calculation is as follows:

• Wall surface: 11 × 4= 44 m2
• PC volume: 8.32 x 44 = 366.08 kg then 366.08 divided by 40 = 9.15 bags of cement
• PP volume: 0.049 x 44 = 2.15 m3 sand
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### 5. Pairs of ½ Brick with Mix 1 PC: 8 PP

So for ½ brick masonry with a mixture of 1 PC: 8 PP, the required composition is 6.5 kg PC and 0.05 m3 PP.

With the size of the wall being built 11 mx 4 m, the calculation is as follows:

• Wall surface: 11 × 4= 44 m2
• PC volume: 6.5 x 44 = 286 kg then 286 divided by 40 = 7.15 bags of cement
• PP volume: 0.05 x 44 = 2.2 m3 sand

## How to calculate the need for cement and sand for plastering In accordance with SNI 2008 and with the stipulation that the size of the wall is 15 x 6 m, the following is the composition of cement and sand and how to calculate:

### 1. Plastering with the composition of 1 PC: 4 PP

Using a ratio of 1 PC: 4 PP, the required composition is cement 6.24 kg / m2 and sand 0.024 m3 / m2.

Then the calculation:

• Cement: (15 x 6) x 6.24 = 561.6 kg, so 561.6 kg divided by 40 = 14.04 bags
• Sand: (15 x 6) x 0.024 = 2.16 m3

### 2. Plastering with the composition of 1 PC: 5 PP

Using a ratio of 1 PC: 5 PP, the required composition is cement 5.18 kg / m2 and sand 0.026 m3 / m2.

Then the calculation:

• Cement: (15 x 6) x 5.18 = 466.2 kg, so 466.2 kg divided by 40 = 11,655 bags
• Sand: (15 x 6) x 0.026 = 2.34 m3

### 3. Plastering with the composition of 1 PC: 6 PP

Using a ratio of 1 PC: 6 PP, the required composition is cement 4.42 kg / m2 and sand 0.027 m3 / m2.

Then the calculation:

• Cement: (15 x 6) x 4.42 = 561.6 kg, so 397.8 kg divided by 40 = 9.945 bags
• Sand: (15 x 6) x 0.027 = 2.43 m3
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## How to calculate the need for cement for the foundation

How to calculate the need for cement for the foundation is a little different from plastering walls.

There are three things to consider when building a foundation, namely thickness, depth and dimensions.

For example, if the foundation you want to build has a length of 38 m, a thickness of 25 cm and a width of 25 cm, the calculation is as follows:

• Volume: 38 mx 0.25 mx 0.25 m = 2.375 m3
• Foundation volume x specific gravity of reinforced concrete: 2,375 m3 x 2,400 kg/m3 = 5,700,000 kg
• Cement requirement: 1/6.5 x 5,700,000 kg = 876.9 kg
• The need for cement: 876.9 kg / 40 kg = 21.9 = 22 bags

Thus, to build a foundation based on these criteria, 22 bags of cement are needed.

## How to calculate cement requirements for floors

With reference to building standards in Indonesia, for a floor measuring 1 m2, 10 kg of concrete is required.

For example, the size of the floor surface to be calculated has a length of 4 m and a width of 3 m, so the calculation is as follows:

• Floor area: 4 mx 3 m = 12 m2
• Concrete requirements: 12 x 10 kg = 120 kg
• Cement requirement: 120 kg / 40 kg = 3 bags

Based on the calculation above, a room of 12 m2 requires 3 bags of cement.

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This is how to calculate the need for cement and sand, Property People.

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